Calculus-Sec-6-1-Solution

6.1 Areas between Curves by SGLee - HSKim, YJLim
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1-21. Find the area of the region, bounded by the given curves.
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http://matrix.skku.ac.kr/cal-lab/cal-6-1-1.html
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. <= 적분구간 (0,1), integral 앞에 2*
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. <= 적분구간을 (0,1) 수정
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x=12 삭제
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21. y=cosx, y= (x-pi/2)*(x+pi/2) (which replace ![]()
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integral(cos(x) - (x-pi/2)*(x+pi/2), x, 0, pi/2) Answer: 1/12*pi^3 + 1
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22-23. Find the integral and interpret it as the area of a region.
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24-25. Approximate the area of the region bounded by the given curves using the Midpoint Rule with
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24.
http://wiki.sagemath.org/interact/calculus#Numerical_integrals_with_various_rules
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26-29. Determine the area of the region bounded by the curves.
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30. Find the area of region defined by the inequalities
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31. Find the area enclosed by the loop of the curve with equation
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(Tschirnhausen's cubic.) http://en.wikipedia.org/wiki/Tschirnhausen_cubic
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32. Find the area of the region bounded by the curve
, the tangent line to this curve at
, and the
-axis.
http://matrix.skku.ac.kr/cal-lab/cal-6-1-32.html
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33. Find the number
such that the line
divides the region bounded by
the curves
and
into two regions with equal area.
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34. (a) Find the number
such that the line
bisects the area under the curve
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(b) Find the number
such that the line
bisects the area in part (a).
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35. Find the values of
such that the area of the region enclosed by the parabolas
and
is 1944.
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For
and
is another solution.
Therefore
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36-40. Find the area of the region bounded by the given curves.
36.
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Since
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37.
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38.
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39.
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