Calculus-Sec-11-5-Solution
11.5 Equations of straight Lines and Planes
by SGLee - HSKim - JHLee
1-7. Find a vector equation, parametric equations and symmetric equations for the line.
1. Through the point and parallel to the vector .
For this line, we have and . Hence a vector equation is
and parametric equations are
.
The symmetric equations are .
2. Through the point and parallel to the vector .
http://matrix.skku.ac.kr/cal-lab/cal-11-5-2.html
(You may do it with Sage in http://math1.skku.ac.kr/ .
Open resources in http://math1.skku.ac.kr/pub/ )
parametric equation: , , ,
symmetric equation: .
3. Through the origin and parallel to the line , , .
This line has the same direction as the vector, .
Here , so a vector equation is and parametric equations are
. The symmetric equations are .
4. Through the point and perpendicular to the plane .
Normal vector : (2, -1, -2)
(ℝ) =>
vector equation: ,
parametric equation: , , ,
symmetric equation: .
5. Through the origin and the point .
For this line, we have and . Hence a vector equation is
and parametric equations are .
The symmetric equations are .
6. Through the points and .
http://matrix.skku.ac.kr/cal-lab/cal-11-5-6.html
parametric equation: , , ,
symmetric equation: .
7. Through and perpendicular to both and .
A line perpendicular to the given two vectors has the same direction as a cross product of the two vectors. That is,
.
Here, , so a vector equation is and
parametric equations are .
The symmetric equations are .
8. Is the line through and parallel to the line through and ?
http://matrix.skku.ac.kr/cal-lab/cal-11-5-8.html
The lines are not parallel because the corresponding vectors
, are not parallel.
9. Is the line through and perpendicular to the line through and ?
Direction vectors of the lines are and .
Since , the vectors and the lines are not perpendicular.
10-13. Determine whether the lines and are parallel, skew, or intersecting. If they intersect, find the point of intersection.
10. : , , ,
: , , .
http://matrix.skku.ac.kr/cal-lab/cal-11-5-10.html
It is apparent that the lines are skew in the following figure.
11. : , , , ℝ.
: , , , ℝ.
Since the direction vectors are and ,
we have . Hence the lines are parallel.
12. : ,
: .
The lines are not parallel because the corresponding vectors , are not parallel.
If and have a point of intersection, there would be values of and such that
,
,
. and are skew.
13. : ,
: .
http://matrix.skku.ac.kr/cal-lab/cal-11-5-13.html
From the figure it is clear that the lines are intersecting.
14-15. Find an equation of the plane.
14. Through the point and perpendicular to the vector .
.
15.Through the point and with normal vector .
is a normal vector to the plane and is a point of the plane.
Then or to be the equation of the plane.
16. Which of the following four planes are parallel?
, ,
, .
and are parallel.
17. Which of the following four lines are parallel?
, ,
, .
and are parallel.
18-19. Find an equation of the plane through the given point with the normal vector
which is the direction of the line with the given parametric equations.
18. , ,
is a normal vector to the plane and is a point of the plane.
Then or to be the equation of the plane.
19. , ,
is a normal vector to the plane and is a point of the plane.
Then or is the equation of the plane.
20-21. Find the distance from the point to the given plane.
20.
http://matrix.skku.ac.kr/cal-lab/cal-11-5-20.html
The normal vector to the plane is n= <2, -1, 3>
21.
The distance .
22-23. Find the distance between the given parallel planes.
22.
: , : . Note that (-1, 0, 1) is a point of the first plane.
Since the planes are parallel, the distance between the two planes is the distance from to the second plane.
Then, the distance between and the plane is
.
23.
Put in the equation of the first plane to get the point on the plane.
Since the planes are parallel, the distance between the two planes is the distance from to the second plane.
Hence .
24. Find the distance between the two skew lines
and .
25. Prove that the distance between the parallel planes and is
.
26. (Line of intersection of two planes)
Plot the two planes and .
Find the line of intersection of two planes and hence plot this.
27. (Line of intersection of two planes)
If the two lines have a point in common then there exists and such that .
The above system must have a unique solution. Let is verify this and find a common point.
Clearly, gives a unique solution and point is the common point.