Calculus-Sec-11-6-Solution
11.6 Cylinders and Quadric Surfaces by SGLee - HSKim - JHLee
1.(a) What does the equation represent as a curve in ?
Equation represents a parabola of slope passing through origin in .
(b) What does it represent as a surface in ?
The equation of the graph is , which doesn't involve in .
This means that any vertical plane with equation (parallel to the plane) intersects the graph in a curve with ,
that is, a parabola. Below figure shows how the graph is formed by taking the parabola in the plane
and moving it in the direction of the axis.
So the graph is a surface, called a parabolic cylinder, made up of infinitely many shifted copies of the same parabola.
(c) What does the equation represent?
also represents a parabolic cylinder, this time with axis the axis in .
(b) Sketch the graph of as a surface in .
(c) Describe and sketch the surface .
6-10. Find the traces of the given surface in , , . Then, identify the surface and sketch it.
6.
http://matrix.skku.ac.kr/cal-lab/cal-11-6-5.html
7.
The trace in are ellipses of the form , ,
the trace in are parabolas of the form ,
and the trace in are parabolas of the form .
Combining these traces we form the graph.
9.
The trace in are hyperbolas of the form ,
the trace in are circles of the form , ,
and the trace in are hyperbolas of the form .
Combining these traces we form the graph.
11-14. Reduce the equation to one of the standard forms, classify the surface, and sketch it.
11.
Dividing both sides by 15 gives ,
an elliptic paraboloid with vertex and axis the horizontal line .
13.
Completing squares in and gives or
, a hyperboloid of one sheet.
16. Sketch the region bounded by the surfaces and for .
http://matrix.skku.ac.kr/cal-lab/cal-11-6-16.html
17. Find an equation for the surface obtained by rotating the parabola about the -axis.
(Use revolution_plot3d to get the plot of this surface.)
18. Find an equation for the surface consisting of all points for which
the distance from to the -axis is twice the distance from to the -plane. Identify the surface.
Let be an arbitrary point whose distance from th axis is twice its distance from the plane.
The distance from to the axis is and the distance from to the plane() is .
Thus .
So, the surface is a right circular cone with vertex the origin and axis the axis.
19. Find an equation for the surface consisting of all points that are equidistant
from the point and the plane .