Calculus-Sec-11-6-Solution

11.6 Cylinders and Quadric Surfaces by SGLee - HSKim - JHLee
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1.(a) What does the equation
represent as a curve in
?
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Equation
represents a parabola of slope
passing through origin in
.
(b) What does it represent as a surface in
?
The equation of the graph is
, which doesn't involve
in
.
This means that any vertical plane with equation
(parallel to the
plane) intersects the graph in a curve with
,
that is, a parabola. Below figure shows how the graph is formed by taking the parabola
in the
plane
and moving it in the direction of the
axis.
So the graph is a surface, called a parabolic cylinder, made up of infinitely many shifted copies of the same parabola.
(c) What does the equation
represent?
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also represents a parabolic cylinder, this time with axis the
axis in
.
(b) Sketch the graph of
as a surface in
.
(c) Describe and sketch the surface
.
6-10. Find the traces of the given surface in
,
,
. Then, identify the surface and sketch it.
6. ![]()
http://matrix.skku.ac.kr/cal-lab/cal-11-6-5.html
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7. ![]()
The trace in
are ellipses of the form
,
,
the trace in
are parabolas of the form
,
and the trace in
are parabolas of the form
.
Combining these traces we form the graph.

9. ![]()
The trace in
are hyperbolas of the form
,
the trace in
are circles of the form
,
,
and the trace in
are hyperbolas of the form
.
Combining these traces we form the graph.

11-14. Reduce the equation to one of the standard forms, classify the surface, and sketch it.
11. ![]()
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Dividing both sides by 15 gives
,
an elliptic paraboloid with vertex
and axis the horizontal line
.

13. ![]()
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Completing squares in
and
gives
or
, a hyperboloid of one sheet.

16. Sketch the region bounded by the surfaces
and
for
.
http://matrix.skku.ac.kr/cal-lab/cal-11-6-16.html
17. Find an equation for the surface obtained by rotating the parabola
about the
-axis.
(Use revolution_plot3d to get the plot of this surface.)
18. Find an equation for the surface consisting of all points
for which
the distance from
to the
-axis is twice the distance from
to the
-plane. Identify the surface.
Let
be an arbitrary point whose distance from th
axis is twice its distance from the
plane.
The distance from
to the
axis is
and the distance from
to the
plane(
) is
.
Thus
.
So, the surface is a right circular cone with vertex the origin and axis the
axis.
19. Find an equation for the surface consisting of all points that are equidistant
from the point
and the plane
.
