Calculus-Sec-12-3-Solution
12.3 Arc Length and Curvature by SGLee - HSKim - JHLee
1-5. Find the length of the curve.
1. ,
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3. ,
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5. ,
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6-8. Reparametrize the curve with respect to arc length measured from the point where in the direction of increasing .
6.
Since , .
Thus , this implies .
Substituting in , we have .
7.
Since , .
Thus .
Substituting in , we have .
9-10. Find the unit tangent , unit normal vectors and the curvature .
9.
, .
Hence .
, .
Hence .
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10. ,
11-13. Use Theorem 7 to find the curvature.
11.
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13.
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14. Find the curvature of at the point .
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, . <-- k(0)=sqrt(2)/5
15. Find the curvature of at the point .
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16-18. Use Formula 6 to find the curvature.
16.
,
. <-- 분자가 2
17.
,
. <-- 분자가 abs(sin x + cos x)
18.
,
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19-20. Find the vectors , and at the given point, and plot at some point.
19. ,
http://matrix.skku.ac.kr/cal-lab/cal-13-3-19.html
21-22. Find equations of the normal plane and osculating plane of the curve at the given point, and plot the graphs.
21.
http://matrix.skku.ac.kr/cal-lab/cal-13-3-21.html
23. At what point on the curve is the tangent plane parallel to the plane .
http://matrix.skku.ac.kr/cal-lab/cal-13-3-23.html
24. The curvature at a point of a curve is defined as ,
when is the angle of inclination of the tangent line at , as shown in the figure.
Thus, the curvature is the absolute value of the rate of change of with respect to arc length.
It can be regarded as a measure of the rate of change of direction of the curve ar
and will be studied in greater detail in Chapter 12.
(a) For a parametric curve , derive the formula
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where the dots indicate derivatives with respect to , that is, . [Hint: Use and Equation to find . Then use the Chain Rule to find .]
(b) For a curve as the parametric curve , , show that the formula in part (a) becomes
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(a) Here ,
, and
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Thus .
(b) Here .
By applying the result of (a) to this case, we obtain that
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25. (a) Show that the curvature at each point of a straight line is .
(b) Show that the curvature at each point of a circle of radius is .
(a) For a straight line, we parametrize . Since is a straight line,
is a constant, and hence is zero. By #30-(b), we have .
(b) . Then,
and . By problem 30 (a), we have .