Calculus-Sec-12-3-Solution
12.3 Arc Length and Curvature by SGLee - HSKim - JHLee
1-5. Find the length of the curve.
1. ,
.
.
.
3. ,
.
.
.
5. ,
,
,
.
6-8. Reparametrize the curve with respect to arc length measured from the point where in the direction of increasing
.
6.
Since ,
.
Thus , this implies
.
Substituting in
, we have
.
7.
Since ,
.
Thus
.
Substituting in
, we have
.
9-10. Find the unit tangent , unit normal vectors
and the curvature
.
9.
,
.
Hence .
,
.
Hence .
.
10.
,
11-13. Use Theorem 7 to find the curvature.
11.
,
,
.
13.
,
.
.
14. Find the curvature of at the point
.
,
,
,
,
,
,
. <-- k(0)=sqrt(2)/5
15. Find the curvature of at the point
.
,
,
,
.
16-18. Use Formula 6 to find the curvature.
16.
,
. <-- 분자가 2
17.
,
. <-- 분자가 abs(sin x + cos x)
18.
,
.
19-20. Find the vectors
,
and
at the given point, and plot at some point.
19. ,
http://matrix.skku.ac.kr/cal-lab/cal-13-3-19.html
21-22. Find equations of the normal plane and osculating plane of the curve at the given point, and plot the graphs.
21.
http://matrix.skku.ac.kr/cal-lab/cal-13-3-21.html
23. At what point on the curve
is the tangent plane parallel to the plane
.
http://matrix.skku.ac.kr/cal-lab/cal-13-3-23.html
24. The curvature at a point of a curve is defined as
,
when is the angle of inclination of the tangent line at
, as shown in the figure.
Thus, the curvature is the absolute value of the rate of change of with respect to arc length.
It can be regarded as a measure of the rate of change of direction of the curve ar
and will be studied in greater detail in Chapter 12.
(a) For a parametric curve ,
derive the formula
.
where the dots indicate derivatives with respect to , that is,
. [Hint: Use
and Equation
to find
. Then use the Chain Rule to find
.]
(b) For a curve as the parametric curve
,
, show that the formula in part (a) becomes
.
(a) Here ,
, and
.
Thus .
(b) Here .
By applying the result of (a) to this case, we obtain that
.
25. (a) Show that the curvature at each point of a straight line is .
(b) Show that the curvature at each point of a circle of radius is
.
(a) For a straight line, we parametrize . Since
is a straight line,
is a constant, and hence
is zero. By #30-(b), we have
.
(b) . Then,
and
. By problem 30 (a), we have
.