2.2 Continuity

1. If and are continuous functions with and , find .

http://matrix.skku.ac.kr/cal-lab/cal-2-2-1.html 

   

   


2. If and are continuous functions with and , find .

   Since is continuous, .


3. Show that the function is discontinuous at .

http://matrix.skku.ac.kr/cal-lab/cal-2-2-3.html 

 We may draw with the following Sage command. It shows the function diverge

      (+infinity) at . This shows f(x) is discontinuous at .


   


   

 

   If we use the following Sage command, we may get limit(abs(ln((x-2)^2))) at directly.

   It shows is discontinuous at .

   

   +Infinity


4-7. Determine the points of discontinuity of . At which of these numbers is continuous from the right, from the left or neither? Sketch the graph of .


4.

        http://matrix.skku.ac.kr/cal-lab/cal-2-2-4.html 

 We may draw with the following Sage command.

      It shows the function is discontinuous at .


   

   



5.

 We see that exists for all except . Notice that the right and left limits are different .

   


6.

 We see that exists for all a except . Notice that the right and left limits are different and  we see that exists for all a except . Notice that the right and left limits are different .


   


7.

 We see that exists for all except . Notice that the right and left limits are different and we see that exists for all except . Notice that the right and left limits are different .


   



8-10. For what values of the constant is the function continuous on ?


8.

   Thus, for to be continuous on

9.

   http://matrix.skku.ac.kr/cal-lab/cal-2-2-9.html  

   

   


10.

   http://matrix.skku.ac.kr/cal-lab/cal-2-2-10.html

  

   

   

   Since is not continuous at , and , the solution is .


11-13. Show that the following functions has the removable discontinuity at . Also find a function that agrees with for and is continuous on ?.


11.

  for . The discontinuity is removable and agrees with for and is continuous on ?.


12.

  for . The discontinuity is removable and agrees with for and is continuous on ?.


13.

  for . The discontinuity is removable and agrees with for and is continuous on ?.


14. Let . Is removable discontinuity?

 Since ,

       is not a removable discontinuity.


15. If , show that there is a number such that .

  is continuous on the interval , and . Since , there is a number in such that by the Intermediate Value Theorem.


16. Prove using Intermediate Value Theorem that there is a positive number such that .

 Let . We know that is continuous on the interval , and . Since , there is a number in such that by the Intermediate Value Theorem.


17-22. Prove that there is a root of the given equation in the specified interval by using the Intermediate Value Theorem.

 17.

   http://matrix.skku.ac.kr/cal-lab/cal-2-2-17.html

   


   


   

    

   

   


 18. ,

   http://matrix.skku.ac.kr/cal-lab/cal-2-2-18.html

   


   


   

   True


   

   True


 19.

   http://matrix.skku.ac.kr/cal-lab/cal-2-2-19.html

   


   


   

   -1


   

   1


20. ,

   http://matrix.skku.ac.kr/cal-lab/cal-2-2-20.html

   


   

   

   True


   

   True


21.

  is continuous on the interval , and .

      Since , there is a number in such that by the Intermediate Value Theorem.

      Thus, there is root of the equation in the interval .


22.

  is continuous on the interval , and . Since –6.696<0<e, there is a number in such that by the Intermediate Value Theorem. Thus, there is root of the equation  in the interval .


23-26. Show that each of the following equations has at least one real root.

23.

   http://matrix.skku.ac.kr/cal-lab/cal-2-2-23.html  

 http://math2.skku.ac.kr/home/pub/37

      We may draw both and in one graph to find intersections. It shows the function has two real roots in  and .


   


           


   The following Sage commands give the value of the intersection in each interval, or .


   

   0.37055809596982464


   

   1.3649584337330951


24.

 Let . Then and . So by the Intermediate Value Theorem.

      There is a number in (-1,0) such that . This implies that .


25.

 Let . Then and . So by the Intermediate Value Theorem.

       There is a number in (1,2) such that . This implies that


26.

 Let . Then and , and is continuous

       So by the Intermediate Value Theorem, there is a number in such that .

       This implies that


27-28. Find the values of for which is continuous.

27.

   is not continuous at each points. So such value of don't exist.


28.

  is continuous at .